What is the value of K for this aqueous reaction at 298 K?

Question

What is the value of K for this aqueous reaction at 298 K?

A + B <—–> C + D   Delta G = 26.81 kJ/mol

Answer

∆G = -RT lnKK = e-∆G/RT∆G/RT = 26.81kJ/mol/(0.008314 kJ/mol-K)(298K) = 10.82K = e-10.82K = 2×10-5

Answered by JRS who is a Ph.D University Professor with 10+ years.

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